Solve 1/3=k/-frac{1{2}-1}

$$\frac { 1 } { 3 } = \frac { k } { - \frac { 1 } { 2 } - 1 }$$

Solve for k

$$k=-\frac{1}{2}=-0.5$$

Steps for Solving Linear Equation

Convert 1 to fraction \frac{2}{2}.

$$\frac{1}{3}=\frac{k}{-\frac{1}{2}-\frac{2}{2}}$$

Since -\frac{1}{2} and \frac{2}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{3}=\frac{k}{\frac{-1-2}{2}}$$

Subtract 2 from -1 to get -3.

$$\frac{1}{3}=\frac{k}{-\frac{3}{2}}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{k}{-\frac{3}{2}}=\frac{1}{3}$$

Multiply both sides by -\frac{3}{2}.

$$k=\frac{1}{3}\left(-\frac{3}{2}\right)$$

Multiply \frac{1}{3} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$k=\frac{1\left(-3\right)}{3\times 2}$$

Do the multiplications in the fraction \frac{1\left(-3\right)}{3\times 2}.

$$k=\frac{-3}{6}$$

Reduce the fraction \frac{-3}{6} to lowest terms by extracting and canceling out 3.

$$k=-\frac{1}{2}$$