Solve 1/3:(22/5-3/5*23/4)=

$$\frac { 1 } { 3 } : ( 2 \frac { 2 } { 5 } - \frac { 3 } { 5 } \cdot 2 \frac { 3 } { 4 } ) =$$

Evaluate

$$\frac{4}{9}\approx 0.444444444$$

Solution Steps

Multiply 2 and 5 to get 10.

$$\frac{\frac{1}{3}}{\frac{10+2}{5}-\frac{3}{5}\times \frac{2\times 4+3}{4}}$$

Add 10 and 2 to get 12.

$$\frac{\frac{1}{3}}{\frac{12}{5}-\frac{3}{5}\times \frac{2\times 4+3}{4}}$$

Multiply 2 and 4 to get 8.

$$\frac{\frac{1}{3}}{\frac{12}{5}-\frac{3}{5}\times \frac{8+3}{4}}$$

Add 8 and 3 to get 11.

$$\frac{\frac{1}{3}}{\frac{12}{5}-\frac{3}{5}\times \frac{11}{4}}$$

Multiply \frac{3}{5} times \frac{11}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{1}{3}}{\frac{12}{5}-\frac{3\times 11}{5\times 4}}$$

Do the multiplications in the fraction \frac{3\times 11}{5\times 4}.

$$\frac{\frac{1}{3}}{\frac{12}{5}-\frac{33}{20}}$$

Least common multiple of 5 and 20 is 20. Convert \frac{12}{5} and \frac{33}{20} to fractions with denominator 20.

$$\frac{\frac{1}{3}}{\frac{48}{20}-\frac{33}{20}}$$

Since \frac{48}{20} and \frac{33}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{1}{3}}{\frac{48-33}{20}}$$

Subtract 33 from 48 to get 15.

$$\frac{\frac{1}{3}}{\frac{15}{20}}$$

Reduce the fraction \frac{15}{20} to lowest terms by extracting and canceling out 5.

$$\frac{\frac{1}{3}}{\frac{3}{4}}$$

Divide \frac{1}{3} by \frac{3}{4} by multiplying \frac{1}{3} by the reciprocal of \frac{3}{4}.

$$\frac{1}{3}\times \frac{4}{3}$$

Multiply \frac{1}{3} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 4}{3\times 3}$$

Do the multiplications in the fraction \frac{1\times 4}{3\times 3}.

$$\frac{4}{9}$$

Factor

$$\frac{2 ^ {2}}{3 ^ {2}} = 0.4444444444444444$$