Solve 1/3:245/3*3/7-1

$$\frac { 1 } { 3 } : \frac { 245 } { 3 } \cdot \frac { 3 } { 7 } - 1$$

Evaluate

$$-\frac{1712}{1715}\approx -0.998250729$$

Solution Steps

Divide \frac{1}{3} by \frac{245}{3} by multiplying \frac{1}{3} by the reciprocal of \frac{245}{3}.

$$\frac{1}{3}\times \frac{3}{245}\times \frac{3}{7}-1$$

Multiply \frac{1}{3} times \frac{3}{245} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 3}{3\times 245}\times \frac{3}{7}-1$$

Cancel out 3 in both numerator and denominator.

$$\frac{1}{245}\times \frac{3}{7}-1$$

Multiply \frac{1}{245} times \frac{3}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 3}{245\times 7}-1$$

Do the multiplications in the fraction \frac{1\times 3}{245\times 7}.

$$\frac{3}{1715}-1$$

Convert 1 to fraction \frac{1715}{1715}.

$$\frac{3}{1715}-\frac{1715}{1715}$$

Since \frac{3}{1715} and \frac{1715}{1715} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-1715}{1715}$$

Subtract 1715 from 3 to get -1712.

$$-\frac{1712}{1715}$$

Factor

$$-\frac{1712}{1715} = -0.9982507288629737$$