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\frac{1}{3}+\frac{5}{4}x-\frac{2}{3}x=\frac{3}{4}
Subtract \frac{2}{3}x from both sides.
\frac{1}{3}+\frac{7}{12}x=\frac{3}{4}
Combine \frac{5}{4}x and -\frac{2}{3}x to get \frac{7}{12}x.
\frac{7}{12}x=\frac{3}{4}-\frac{1}{3}
Subtract \frac{1}{3} from both sides.
\frac{7}{12}x=\frac{9}{12}-\frac{4}{12}
Least common multiple of 4 and 3 is 12. Convert \frac{3}{4} and \frac{1}{3} to fractions with denominator 12.
\frac{7}{12}x=\frac{9-4}{12}
Since \frac{9}{12} and \frac{4}{12} have the same denominator, subtract them by subtracting their numerators.
\frac{7}{12}x=\frac{5}{12}
Subtract 4 from 9 to get 5.
x=\frac{5}{12}\times \frac{12}{7}
Multiply both sides by \frac{12}{7}, the reciprocal of \frac{7}{12}.
x=\frac{5\times 12}{12\times 7}
Multiply \frac{5}{12} times \frac{12}{7} by multiplying numerator times numerator and denominator times denominator.
x=\frac{5}{7}
Cancel out 12 in both numerator and denominator.