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\frac{1}{3}+\frac{4}{9}\times \frac{3}{2}
Divide \frac{4}{9} by \frac{2}{3} by multiplying \frac{4}{9} by the reciprocal of \frac{2}{3}.
\frac{1}{3}+\frac{4\times 3}{9\times 2}
Multiply \frac{4}{9} times \frac{3}{2} by multiplying numerator times numerator and denominator times denominator.
\frac{1}{3}+\frac{12}{18}
Do the multiplications in the fraction \frac{4\times 3}{9\times 2}.
\frac{1}{3}+\frac{2}{3}
Reduce the fraction \frac{12}{18} to lowest terms by extracting and canceling out 6.
\frac{1+2}{3}
Since \frac{1}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.
\frac{3}{3}
Add 1 and 2 to get 3.
1
Divide 3 by 3 to get 1.