Solve 1/3+3/6-1/9

$$\frac { 1 } { 3 } + \frac { 3 } { 6 } - \frac { 1 } { 9 }$$

Evaluate

$$\frac{13}{18}\approx 0.722222222$$

Solution Steps

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{1}{3}+\frac{1}{2}-\frac{1}{9}$$

Least common multiple of 3 and 2 is 6. Convert \frac{1}{3} and \frac{1}{2} to fractions with denominator 6.

$$\frac{2}{6}+\frac{3}{6}-\frac{1}{9}$$

Since \frac{2}{6} and \frac{3}{6} have the same denominator, add them by adding their numerators.

$$\frac{2+3}{6}-\frac{1}{9}$$

Add 2 and 3 to get 5.

$$\frac{5}{6}-\frac{1}{9}$$

Least common multiple of 6 and 9 is 18. Convert \frac{5}{6} and \frac{1}{9} to fractions with denominator 18.

$$\frac{15}{18}-\frac{2}{18}$$

Since \frac{15}{18} and \frac{2}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{15-2}{18}$$

Subtract 2 from 15 to get 13.

$$\frac{13}{18}$$

Factor

$$\frac{13}{2 \cdot 3 ^ {2}} = 0.7222222222222222$$