Solve 1/3+3/4*1/3-1/4

$$\frac { 1 } { 3 } + \frac { 3 } { 4 } \cdot \frac { 1 } { 3 } - \frac { 1 } { 4 }$$

Evaluate

$$\frac{1}{3}\approx 0.333333333$$

Solution Steps

Multiply \frac{3}{4} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{3}+\frac{3\times 1}{4\times 3}-\frac{1}{4}$$

Cancel out 3 in both numerator and denominator.

$$\frac{1}{3}+\frac{1}{4}-\frac{1}{4}$$

Least common multiple of 3 and 4 is 12. Convert \frac{1}{3} and \frac{1}{4} to fractions with denominator 12.

$$\frac{4}{12}+\frac{3}{12}-\frac{1}{4}$$

Since \frac{4}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.

$$\frac{4+3}{12}-\frac{1}{4}$$

Add 4 and 3 to get 7.

$$\frac{7}{12}-\frac{1}{4}$$

Least common multiple of 12 and 4 is 12. Convert \frac{7}{12} and \frac{1}{4} to fractions with denominator 12.

$$\frac{7}{12}-\frac{3}{12}$$

Since \frac{7}{12} and \frac{3}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-3}{12}$$

Subtract 3 from 7 to get 4.

$$\frac{4}{12}$$

Reduce the fraction \frac{4}{12} to lowest terms by extracting and canceling out 4.

$$\frac{1}{3}$$

Factor

$$\frac{1}{3} = 0.3333333333333333$$