Solve 1/3+1/6=3/6=1/2frac{6}{3}

$$\frac { 1 } { 3 } + \frac { 1 } { 6 } = \frac { 3 } { 6 } = \frac { 1 } { 2 } \frac { 6 } { 3 }$$

Verify

Solution Steps

Least common multiple of 3 and 6 is 6. Convert \frac{1}{3} and \frac{1}{6} to fractions with denominator 6.

$$\frac{2}{6}+\frac{1}{6}=\frac{3}{6}\text{ and }\frac{3}{6}=\frac{1}{2}\times \frac{6}{3}$$

Since \frac{2}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$\frac{2+1}{6}=\frac{3}{6}\text{ and }\frac{3}{6}=\frac{1}{2}\times \frac{6}{3}$$

Add 2 and 1 to get 3.

$$\frac{3}{6}=\frac{3}{6}\text{ and }\frac{3}{6}=\frac{1}{2}\times \frac{6}{3}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{1}{2}=\frac{3}{6}\text{ and }\frac{3}{6}=\frac{1}{2}\times \frac{6}{3}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{1}{2}=\frac{1}{2}\text{ and }\frac{3}{6}=\frac{1}{2}\times \frac{6}{3}$$

Compare \frac{1}{2} and \frac{1}{2}.

$$\text{true}\text{ and }\frac{3}{6}=\frac{1}{2}\times \frac{6}{3}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\text{true}\text{ and }\frac{1}{2}=\frac{1}{2}\times \frac{6}{3}$$

Divide 6 by 3 to get 2.

$$\text{true}\text{ and }\frac{1}{2}=\frac{1}{2}\times 2$$

Cancel out 2 and 2.

$$\text{true}\text{ and }\frac{1}{2}=1$$

Convert 1 to fraction \frac{2}{2}.

$$\text{true}\text{ and }\frac{1}{2}=\frac{2}{2}$$

Compare \frac{1}{2} and \frac{2}{2}.

$$\text{true}\text{ and }\text{false}$$

The conjunction of \text{true} and \text{false} is \text{false}.

$$\text{false}$$