Solve 1/3+1/3-3-3=

$$\frac { 1 } { 3 } + \frac { 1 } { 3 } - 3 - 3 =$$

Evaluate

$$-\frac{16}{3}\approx -5.333333333$$

Solution Steps

Since \frac{1}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{1+1}{3}-3-3$$

Add 1 and 1 to get 2.

$$\frac{2}{3}-3-3$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{2}{3}-\frac{9}{3}-3$$

Since \frac{2}{3} and \frac{9}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{2-9}{3}-3$$

Subtract 9 from 2 to get -7.

$$-\frac{7}{3}-3$$

Convert 3 to fraction \frac{9}{3}.

$$-\frac{7}{3}-\frac{9}{3}$$

Since -\frac{7}{3} and \frac{9}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-7-9}{3}$$

Subtract 9 from -7 to get -16.

$$-\frac{16}{3}$$

Factor

$$-\frac{16}{3} = -5\frac{1}{3} = -5.333333333333333$$