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\frac{125x^{3}+27y^{3}}{3375}
Factor out \frac{1}{3375}.
\left(5x+3y\right)\left(25x^{2}-15xy+9y^{2}\right)
Consider 125x^{3}+27y^{3}. Rewrite 125x^{3}+27y^{3} as \left(5x\right)^{3}+\left(3y\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
\frac{\left(5x+3y\right)\left(25x^{2}-15xy+9y^{2}\right)}{3375}
Rewrite the complete factored expression.