Solve 1/2016*2018+1/2018*2020

$$\frac { 1 } { 2016 \times 2018 } + \frac { 1 } { 2018 \times 2020 }$$

Evaluate

$$\frac{1}{2036160}\approx 0.000000491$$

Solution Steps

Multiply 2016 and 2018 to get 4068288.

$$\frac{1}{4068288}+\frac{1}{2018\times 2020}$$

Multiply 2018 and 2020 to get 4076360.

$$\frac{1}{4068288}+\frac{1}{4076360}$$

Least common multiple of 4068288 and 4076360 is 2054485440. Convert \frac{1}{4068288} and \frac{1}{4076360} to fractions with denominator 2054485440.

$$\frac{505}{2054485440}+\frac{504}{2054485440}$$

Since \frac{505}{2054485440} and \frac{504}{2054485440} have the same denominator, add them by adding their numerators.

$$\frac{505+504}{2054485440}$$

Add 505 and 504 to get 1009.

$$\frac{1009}{2054485440}$$

Reduce the fraction \frac{1009}{2054485440} to lowest terms by extracting and canceling out 1009.

$$\frac{1}{2036160}$$

Factor

$$\frac{1}{2 ^ {6} \cdot 3 ^ {2} \cdot 5 \cdot 7 \cdot 101} = 4.911205406254911 \times 10^{-7}$$