Solve 1/200+2/R=1/80

$$\frac { 1 } { 200 } + \frac { 2 } { R } = \frac { 1 } { 80 }$$

Solve for R

$$R = \frac{800}{3} = 266\frac{2}{3} \approx 266.666666667$$

Steps for Solving Linear Equation

Variable R cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 400R, the least common multiple of 200,R,80.

$$400R\times \frac{1}{200}+400\times 2=5R$$

Multiply 400 and \frac{1}{200} to get \frac{400}{200}.

$$\frac{400}{200}R+400\times 2=5R$$

Divide 400 by 200 to get 2.

$$2R+400\times 2=5R$$

Multiply 400 and 2 to get 800.

$$2R+800=5R$$

Subtract 5R from both sides.

$$2R+800-5R=0$$

Combine 2R and -5R to get -3R.

$$-3R+800=0$$

Subtract 800 from both sides. Anything subtracted from zero gives its negation.

$$-3R=-800$$

Divide both sides by -3.

$$R=\frac{-800}{-3}$$

Fraction \frac{-800}{-3} can be simplified to \frac{800}{3} by removing the negative sign from both the numerator and the denominator.

$$R=\frac{800}{3}$$