Solve 1/2y-3*6/3-y=

$$\frac { 1 } { 2 y - 3 } * \frac { 6 } { 3 - y } =$$

Evaluate

$$\frac{6}{\left(3-y\right)\left(2y-3\right)}$$

Solution Steps

Multiply \frac{1}{2y-3} times \frac{6}{3-y} by multiplying numerator times numerator and denominator times denominator.

$$\frac{6}{\left(2y-3\right)\left(3-y\right)}$$

Apply the distributive property by multiplying each term of 2y-3 by each term of 3-y.

$$\frac{6}{6y-2y^{2}-9+3y}$$

Combine 6y and 3y to get 9y.

$$\frac{6}{9y-2y^{2}-9}$$

Differentiate w.r.t. y

$$\frac{6\left(9-4y\right)}{\left(3-y\right)\left(y-3\right)\left(2y-3\right)^{2}}$$