Solve for y
y=12
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\frac{1}{2}y-2-\frac{1}{3}y=0
Subtract \frac{1}{3}y from both sides.
\frac{1}{6}y-2=0
Combine \frac{1}{2}y and -\frac{1}{3}y to get \frac{1}{6}y.
\frac{1}{6}y=2
Add 2 to both sides. Anything plus zero gives itself.
y=2\times 6
Multiply both sides by 6, the reciprocal of \frac{1}{6}.
y=12
Multiply 2 and 6 to get 12.
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