Solve for x
x=8y-6
Solve for y
y=\frac{x+6}{8}
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\frac{1}{2}x=-3+4y
Add 4y to both sides.
\frac{1}{2}x=4y-3
The equation is in standard form.
\frac{\frac{1}{2}x}{\frac{1}{2}}=\frac{4y-3}{\frac{1}{2}}
Multiply both sides by 2.
x=\frac{4y-3}{\frac{1}{2}}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
x=8y-6
Divide -3+4y by \frac{1}{2} by multiplying -3+4y by the reciprocal of \frac{1}{2}.
-4y=-3-\frac{1}{2}x
Subtract \frac{1}{2}x from both sides.
-4y=-\frac{x}{2}-3
The equation is in standard form.
\frac{-4y}{-4}=\frac{-\frac{x}{2}-3}{-4}
Divide both sides by -4.
y=\frac{-\frac{x}{2}-3}{-4}
Dividing by -4 undoes the multiplication by -4.
y=\frac{x}{8}+\frac{3}{4}
Divide -3-\frac{x}{2} by -4.
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