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\frac{1}{7}x+\frac{1}{2}=\frac{5}{7}-\frac{2}{7}x
Combine \frac{1}{2}x and -\frac{5}{14}x to get \frac{1}{7}x.
\frac{1}{7}x+\frac{1}{2}+\frac{2}{7}x=\frac{5}{7}
Add \frac{2}{7}x to both sides.
\frac{3}{7}x+\frac{1}{2}=\frac{5}{7}
Combine \frac{1}{7}x and \frac{2}{7}x to get \frac{3}{7}x.
\frac{3}{7}x=\frac{5}{7}-\frac{1}{2}
Subtract \frac{1}{2} from both sides.
\frac{3}{7}x=\frac{10}{14}-\frac{7}{14}
Least common multiple of 7 and 2 is 14. Convert \frac{5}{7} and \frac{1}{2} to fractions with denominator 14.
\frac{3}{7}x=\frac{10-7}{14}
Since \frac{10}{14} and \frac{7}{14} have the same denominator, subtract them by subtracting their numerators.
\frac{3}{7}x=\frac{3}{14}
Subtract 7 from 10 to get 3.
x=\frac{3}{14}\times \frac{7}{3}
Multiply both sides by \frac{7}{3}, the reciprocal of \frac{3}{7}.
x=\frac{3\times 7}{14\times 3}
Multiply \frac{3}{14} times \frac{7}{3} by multiplying numerator times numerator and denominator times denominator.
x=\frac{7}{14}
Cancel out 3 in both numerator and denominator.
x=\frac{1}{2}
Reduce the fraction \frac{7}{14} to lowest terms by extracting and canceling out 7.