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\frac{1}{2}x-\frac{2}{3}-\frac{1}{6}x=-1
Subtract \frac{1}{6}x from both sides.
\frac{1}{3}x-\frac{2}{3}=-1
Combine \frac{1}{2}x and -\frac{1}{6}x to get \frac{1}{3}x.
\frac{1}{3}x=-1+\frac{2}{3}
Add \frac{2}{3} to both sides.
\frac{1}{3}x=-\frac{3}{3}+\frac{2}{3}
Convert -1 to fraction -\frac{3}{3}.
\frac{1}{3}x=\frac{-3+2}{3}
Since -\frac{3}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.
\frac{1}{3}x=-\frac{1}{3}
Add -3 and 2 to get -1.
x=-\frac{1}{3}\times 3
Multiply both sides by 3, the reciprocal of \frac{1}{3}.
x=-1
Cancel out 3 and 3.