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\frac{1}{2}x=2+\frac{1}{8}y
Add \frac{1}{8}y to both sides.
\frac{1}{2}x=\frac{y}{8}+2
The equation is in standard form.
\frac{\frac{1}{2}x}{\frac{1}{2}}=\frac{\frac{y}{8}+2}{\frac{1}{2}}
Multiply both sides by 2.
x=\frac{\frac{y}{8}+2}{\frac{1}{2}}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
x=\frac{y}{4}+4
Divide 2+\frac{y}{8} by \frac{1}{2} by multiplying 2+\frac{y}{8} by the reciprocal of \frac{1}{2}.
-\frac{1}{8}y=2-\frac{1}{2}x
Subtract \frac{1}{2}x from both sides.
-\frac{1}{8}y=-\frac{x}{2}+2
The equation is in standard form.
\frac{-\frac{1}{8}y}{-\frac{1}{8}}=\frac{-\frac{x}{2}+2}{-\frac{1}{8}}
Multiply both sides by -8.
y=\frac{-\frac{x}{2}+2}{-\frac{1}{8}}
Dividing by -\frac{1}{8} undoes the multiplication by -\frac{1}{8}.
y=4x-16
Divide 2-\frac{x}{2} by -\frac{1}{8} by multiplying 2-\frac{x}{2} by the reciprocal of -\frac{1}{8}.