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\frac{1}{2}x+\frac{3}{2}x\leq 8
Add \frac{3}{2}x to both sides.
2x\leq 8
Combine \frac{1}{2}x and \frac{3}{2}x to get 2x.
x\leq \frac{8}{2}
Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.
x\leq 4
Divide 8 by 2 to get 4.