Solve for x
x=10\left(y-3\right)
Solve for y
y=\frac{x+30}{10}
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\frac{1}{2}x=5y-15
The equation is in standard form.
\frac{\frac{1}{2}x}{\frac{1}{2}}=\frac{5y-15}{\frac{1}{2}}
Multiply both sides by 2.
x=\frac{5y-15}{\frac{1}{2}}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
x=10y-30
Divide -15+5y by \frac{1}{2} by multiplying -15+5y by the reciprocal of \frac{1}{2}.
5y-15=\frac{1}{2}x
Swap sides so that all variable terms are on the left hand side.
5y=\frac{1}{2}x+15
Add 15 to both sides.
5y=\frac{x}{2}+15
The equation is in standard form.
\frac{5y}{5}=\frac{\frac{x}{2}+15}{5}
Divide both sides by 5.
y=\frac{\frac{x}{2}+15}{5}
Dividing by 5 undoes the multiplication by 5.
y=\frac{x}{10}+3
Divide \frac{x}{2}+15 by 5.
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