Solve for x
x=-12
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\frac{1}{2}x+2-\frac{1}{3}x=0
Subtract \frac{1}{3}x from both sides.
\frac{1}{6}x+2=0
Combine \frac{1}{2}x and -\frac{1}{3}x to get \frac{1}{6}x.
\frac{1}{6}x=-2
Subtract 2 from both sides. Anything subtracted from zero gives its negation.
x=-2\times 6
Multiply both sides by 6, the reciprocal of \frac{1}{6}.
x=-12
Multiply -2 and 6 to get -12.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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