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\frac{1}{2}x+\frac{1}{4}z=14-\frac{1}{5}y
Subtract \frac{1}{5}y from both sides.
\frac{1}{2}x=14-\frac{1}{5}y-\frac{1}{4}z
Subtract \frac{1}{4}z from both sides.
\frac{1}{2}x=-\frac{y}{5}-\frac{z}{4}+14
The equation is in standard form.
\frac{\frac{1}{2}x}{\frac{1}{2}}=\frac{-\frac{y}{5}-\frac{z}{4}+14}{\frac{1}{2}}
Multiply both sides by 2.
x=\frac{-\frac{y}{5}-\frac{z}{4}+14}{\frac{1}{2}}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
x=-\frac{z}{2}-\frac{2y}{5}+28
Divide 14-\frac{y}{5}-\frac{z}{4} by \frac{1}{2} by multiplying 14-\frac{y}{5}-\frac{z}{4} by the reciprocal of \frac{1}{2}.
\frac{1}{5}y+\frac{1}{4}z=14-\frac{1}{2}x
Subtract \frac{1}{2}x from both sides.
\frac{1}{5}y=14-\frac{1}{2}x-\frac{1}{4}z
Subtract \frac{1}{4}z from both sides.
\frac{1}{5}y=-\frac{x}{2}-\frac{z}{4}+14
The equation is in standard form.
\frac{\frac{1}{5}y}{\frac{1}{5}}=\frac{-\frac{x}{2}-\frac{z}{4}+14}{\frac{1}{5}}
Multiply both sides by 5.
y=\frac{-\frac{x}{2}-\frac{z}{4}+14}{\frac{1}{5}}
Dividing by \frac{1}{5} undoes the multiplication by \frac{1}{5}.
y=-\frac{5x}{2}-\frac{5z}{4}+70
Divide 14-\frac{x}{2}-\frac{z}{4} by \frac{1}{5} by multiplying 14-\frac{x}{2}-\frac{z}{4} by the reciprocal of \frac{1}{5}.