Solve for x
x=14
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\frac{1}{2}x+\frac{1}{5}x+\frac{1}{5}+\frac{1}{4}\left(x+2\right)=14
Use the distributive property to multiply \frac{1}{5} by x+1.
\frac{7}{10}x+\frac{1}{5}+\frac{1}{4}\left(x+2\right)=14
Combine \frac{1}{2}x and \frac{1}{5}x to get \frac{7}{10}x.
\frac{7}{10}x+\frac{1}{5}+\frac{1}{4}x+\frac{1}{4}\times 2=14
Use the distributive property to multiply \frac{1}{4} by x+2.
\frac{7}{10}x+\frac{1}{5}+\frac{1}{4}x+\frac{2}{4}=14
Multiply \frac{1}{4} and 2 to get \frac{2}{4}.
\frac{7}{10}x+\frac{1}{5}+\frac{1}{4}x+\frac{1}{2}=14
Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.
\frac{19}{20}x+\frac{1}{5}+\frac{1}{2}=14
Combine \frac{7}{10}x and \frac{1}{4}x to get \frac{19}{20}x.
\frac{19}{20}x+\frac{2}{10}+\frac{5}{10}=14
Least common multiple of 5 and 2 is 10. Convert \frac{1}{5} and \frac{1}{2} to fractions with denominator 10.
\frac{19}{20}x+\frac{2+5}{10}=14
Since \frac{2}{10} and \frac{5}{10} have the same denominator, add them by adding their numerators.
\frac{19}{20}x+\frac{7}{10}=14
Add 2 and 5 to get 7.
\frac{19}{20}x=14-\frac{7}{10}
Subtract \frac{7}{10} from both sides.
\frac{19}{20}x=\frac{140}{10}-\frac{7}{10}
Convert 14 to fraction \frac{140}{10}.
\frac{19}{20}x=\frac{140-7}{10}
Since \frac{140}{10} and \frac{7}{10} have the same denominator, subtract them by subtracting their numerators.
\frac{19}{20}x=\frac{133}{10}
Subtract 7 from 140 to get 133.
x=\frac{133}{10}\times \frac{20}{19}
Multiply both sides by \frac{20}{19}, the reciprocal of \frac{19}{20}.
x=\frac{133\times 20}{10\times 19}
Multiply \frac{133}{10} times \frac{20}{19} by multiplying numerator times numerator and denominator times denominator.
x=\frac{2660}{190}
Do the multiplications in the fraction \frac{133\times 20}{10\times 19}.
x=14
Divide 2660 by 190 to get 14.
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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