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\frac{1}{2}x=\frac{17}{6}-\frac{1}{3}
Subtract \frac{1}{3} from both sides.
\frac{1}{2}x=\frac{17}{6}-\frac{2}{6}
Least common multiple of 6 and 3 is 6. Convert \frac{17}{6} and \frac{1}{3} to fractions with denominator 6.
\frac{1}{2}x=\frac{17-2}{6}
Since \frac{17}{6} and \frac{2}{6} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{2}x=\frac{15}{6}
Subtract 2 from 17 to get 15.
\frac{1}{2}x=\frac{5}{2}
Reduce the fraction \frac{15}{6} to lowest terms by extracting and canceling out 3.
x=\frac{5}{2}\times 2
Multiply both sides by 2, the reciprocal of \frac{1}{2}.
x=5
Cancel out 2 and 2.