Solve 1/2t+1/3=1/6t-1/3

$$\frac { 1 } { 2 } t + \frac { 1 } { 3 } = \frac { 1 } { 6 } t - \frac { 1 } { 3 }$$

Solve for t

$$t=-2$$

Steps for Solving Linear Equation

Subtract \frac{1}{6}t from both sides.

$$\frac{1}{2}t+\frac{1}{3}-\frac{1}{6}t=-\frac{1}{3}$$

Combine \frac{1}{2}t and -\frac{1}{6}t to get \frac{1}{3}t.

$$\frac{1}{3}t+\frac{1}{3}=-\frac{1}{3}$$

Subtract \frac{1}{3} from both sides.

$$\frac{1}{3}t=-\frac{1}{3}-\frac{1}{3}$$

Since -\frac{1}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{3}t=\frac{-1-1}{3}$$

Subtract 1 from -1 to get -2.

$$\frac{1}{3}t=-\frac{2}{3}$$

Multiply both sides by 3, the reciprocal of \frac{1}{3}.

$$t=-\frac{2}{3}\times 3$$

Cancel out 3 and 3.

$$t=-2$$