Solve 1/2(-3)+(1/3*6--3)

$$\frac { 1 } { 2 } ( - 3 ) + ( \frac { 1 } { 3 } \cdot 6 - - 3 )$$

Evaluate

$$\frac{7}{2}=3.5$$

Solution Steps

Multiply \frac{1}{2} and -3 to get \frac{-3}{2}.

$$\frac{-3}{2}+\frac{1}{3}\times 6-\left(-3\right)$$

Fraction \frac{-3}{2} can be rewritten as -\frac{3}{2} by extracting the negative sign.

$$-\frac{3}{2}+\frac{1}{3}\times 6-\left(-3\right)$$

Multiply \frac{1}{3} and 6 to get \frac{6}{3}.

$$-\frac{3}{2}+\frac{6}{3}-\left(-3\right)$$

Divide 6 by 3 to get 2.

$$-\frac{3}{2}+2-\left(-3\right)$$

The opposite of -3 is 3.

$$-\frac{3}{2}+2+3$$

Add 2 and 3 to get 5.

$$-\frac{3}{2}+5$$

Convert 5 to fraction \frac{10}{2}.

$$-\frac{3}{2}+\frac{10}{2}$$

Since -\frac{3}{2} and \frac{10}{2} have the same denominator, add them by adding their numerators.

$$\frac{-3+10}{2}$$

Add -3 and 10 to get 7.

$$\frac{7}{2}$$

Factor

$$\frac{7}{2} = 3\frac{1}{2} = 3.5$$