Solve 1/2(-1(16-20)+1(8-7)+1(10*2))

$$\frac { 1 } { 2 } ( - 1 ( 16 - 20 ) + 1 ( 8 - 7 ) + 1 ( 10 \cdot 2 ) )$$

Evaluate

$$\frac{25}{2}=12.5$$

Solution Steps

Subtract 20 from 16 to get -4.

$$\frac{1}{2}\left(-\left(-4\right)+1\left(8-7\right)+1\times 10\times 2\right)$$

Multiply -1 and -4 to get 4.

$$\frac{1}{2}\left(4+1\left(8-7\right)+1\times 10\times 2\right)$$

Subtract 7 from 8 to get 1.

$$\frac{1}{2}\left(4+1\times 1+1\times 10\times 2\right)$$

Multiply 1 and 1 to get 1.

$$\frac{1}{2}\left(4+1+1\times 10\times 2\right)$$

Add 4 and 1 to get 5.

$$\frac{1}{2}\left(5+1\times 10\times 2\right)$$

Multiply 1 and 10 to get 10.

$$\frac{1}{2}\left(5+10\times 2\right)$$

Multiply 10 and 2 to get 20.

$$\frac{1}{2}\left(5+20\right)$$

Add 5 and 20 to get 25.

$$\frac{1}{2}\times 25$$

Multiply \frac{1}{2} and 25 to get \frac{25}{2}.

$$\frac{25}{2}$$

Factor

$$\frac{5 ^ {2}}{2} = 12\frac{1}{2} = 12.5$$