Solve 1/2(3/64+3/32)

$$\frac { 1 } { 2 } ( \frac { 3 } { 64 } + \frac { 3 } { 32 } )$$

Evaluate

$$\frac{9}{128}=0.0703125$$

Solution Steps

Least common multiple of 64 and 32 is 64. Convert \frac{3}{64} and \frac{3}{32} to fractions with denominator 64.

$$\frac{1}{2}\left(\frac{3}{64}+\frac{6}{64}\right)$$

Since \frac{3}{64} and \frac{6}{64} have the same denominator, add them by adding their numerators.

$$\frac{1}{2}\times \frac{3+6}{64}$$

Add 3 and 6 to get 9.

$$\frac{1}{2}\times \frac{9}{64}$$

Multiply \frac{1}{2} times \frac{9}{64} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 9}{2\times 64}$$

Do the multiplications in the fraction \frac{1\times 9}{2\times 64}.

$$\frac{9}{128}$$

Factor

$$\frac{3 ^ {2}}{2 ^ {7}} = 0.0703125$$