Solve 1/2(23/256+3/32)=

$$\frac { 1 } { 2 } ( \frac { 23 } { 256 } + \frac { 3 } { 32 } ) =$$

Evaluate

$$\frac{47}{512}=0.091796875$$

Solution Steps

Least common multiple of 256 and 32 is 256. Convert \frac{23}{256} and \frac{3}{32} to fractions with denominator 256.

$$\frac{1}{2}\left(\frac{23}{256}+\frac{24}{256}\right)$$

Since \frac{23}{256} and \frac{24}{256} have the same denominator, add them by adding their numerators.

$$\frac{1}{2}\times \frac{23+24}{256}$$

Add 23 and 24 to get 47.

$$\frac{1}{2}\times \frac{47}{256}$$

Multiply \frac{1}{2} times \frac{47}{256} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 47}{2\times 256}$$

Do the multiplications in the fraction \frac{1\times 47}{2\times 256}.

$$\frac{47}{512}$$

Factor

$$\frac{47}{2 ^ {9}} = 0.091796875$$