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\frac{1}{2}-2x\leq \frac{1}{4}\times 2
Multiply both sides by 2, the reciprocal of \frac{1}{2}. Since \frac{1}{2} is positive, the inequality direction remains the same.
\frac{1}{2}-2x\leq \frac{2}{4}
Multiply \frac{1}{4} and 2 to get \frac{2}{4}.
\frac{1}{2}-2x\leq \frac{1}{2}
Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.
-2x\leq \frac{1}{2}-\frac{1}{2}
Subtract \frac{1}{2} from both sides.
-2x\leq 0
Subtract \frac{1}{2} from \frac{1}{2} to get 0.
x\geq 0
Product of two numbers is ≤0 if one is ≥0 and the other is ≤0. Since -2\leq 0, x must be ≥0.