Solve 1/2[1(1-2)+0(2-0)+1(0-1)]

$$\frac { 1 } { 2 } [ 1 ( 1 - 2 ) + 0 ( 2 - 0 ) + 1 ( 0 - 1 ) ]$$

Evaluate

$$-1$$

Solution Steps

Subtract 2 from 1 to get -1.

$$\frac{1}{2}\left(1\left(-1\right)+0\left(2-0\right)+1\left(0-1\right)\right)$$

Multiply 1 and -1 to get -1.

$$\frac{1}{2}\left(-1+0\left(2-0\right)+1\left(0-1\right)\right)$$

Subtract 0 from 2 to get 2.

$$\frac{1}{2}\left(-1+0\times 2+1\left(0-1\right)\right)$$

Multiply 0 and 2 to get 0.

$$\frac{1}{2}\left(-1+0+1\left(0-1\right)\right)$$

Add -1 and 0 to get -1.

$$\frac{1}{2}\left(-1+1\left(0-1\right)\right)$$

Subtract 1 from 0 to get -1.

$$\frac{1}{2}\left(-1+1\left(-1\right)\right)$$

Multiply 1 and -1 to get -1.

$$\frac{1}{2}\left(-1-1\right)$$

Subtract 1 from -1 to get -2.

$$\frac{1}{2}\left(-2\right)$$

Multiply \frac{1}{2} and -2 to get \frac{-2}{2}.

$$\frac{-2}{2}$$

Divide -2 by 2 to get -1.

$$-1$$

Factor

$$-1$$