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Solve for t
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1.06^{t}=\frac{1}{2}
Swap sides so that all variable terms are on the left hand side.
\log(1.06^{t})=\log(\frac{1}{2})
Take the logarithm of both sides of the equation.
t\log(1.06)=\log(\frac{1}{2})
The logarithm of a number raised to a power is the power times the logarithm of the number.
t=\frac{\log(\frac{1}{2})}{\log(1.06)}
Divide both sides by \log(1.06).
t=\log_{1.06}\left(\frac{1}{2}\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).