Solve 1/2=3/5-QADB

$$\frac { 1 } { 2 } = \frac { 3 } { 5 } - Q A D B$$

Solve for A

$$A=\frac{1}{10BDQ}$$

$$B\neq 0\text{ and }D\neq 0\text{ and }Q\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{3}{5}-QADB=\frac{1}{2}$$

Subtract \frac{3}{5} from both sides.

$$-QADB=\frac{1}{2}-\frac{3}{5}$$

Subtract \frac{3}{5} from \frac{1}{2} to get -\frac{1}{10}.

$$-QADB=-\frac{1}{10}$$

The equation is in standard form.

$$\left(-BDQ\right)A=-\frac{1}{10}$$

Divide both sides by -QDB.

$$\frac{\left(-BDQ\right)A}{-BDQ}=-\frac{\frac{1}{10}}{-BDQ}$$

Dividing by -QDB undoes the multiplication by -QDB.

$$A=-\frac{\frac{1}{10}}{-BDQ}$$

Divide -\frac{1}{10} by -QDB.

$$A=\frac{1}{10BDQ}$$

Solve for B

$$B=\frac{1}{10ADQ}$$

$$D\neq 0\text{ and }A\neq 0\text{ and }Q\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{3}{5}-QADB=\frac{1}{2}$$

Subtract \frac{3}{5} from both sides.

$$-QADB=\frac{1}{2}-\frac{3}{5}$$

Subtract \frac{3}{5} from \frac{1}{2} to get -\frac{1}{10}.

$$-QADB=-\frac{1}{10}$$

The equation is in standard form.

$$\left(-ADQ\right)B=-\frac{1}{10}$$

Divide both sides by -QAD.

$$\frac{\left(-ADQ\right)B}{-ADQ}=-\frac{\frac{1}{10}}{-ADQ}$$

Dividing by -QAD undoes the multiplication by -QAD.

$$B=-\frac{\frac{1}{10}}{-ADQ}$$

Divide -\frac{1}{10} by -QAD.

$$B=\frac{1}{10ADQ}$$