Solve 1/2=1/3*(0.5)^3-2*(0.5)^2+c

$$\frac { 1 } { 2 } = \frac { 1 } { 3 } \times ( 0.5 ) ^ { 3 } - 2 \times ( 0.5 ) ^ { 2 } + c$$

Solve for c

$$c=\frac{23}{24}\approx 0.958333333$$

Steps for Solving Linear Equation

Calculate 0.5 to the power of 3 and get 0.125.

$$\frac{1}{2}=\frac{1}{3}\times 0.125-2\times 0.5^{2}+c$$

Convert decimal number 0.125 to fraction \frac{125}{1000}. Reduce the fraction \frac{125}{1000} to lowest terms by extracting and canceling out 125.

$$\frac{1}{2}=\frac{1}{3}\times \frac{1}{8}-2\times 0.5^{2}+c$$

Multiply \frac{1}{3} times \frac{1}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{2}=\frac{1\times 1}{3\times 8}-2\times 0.5^{2}+c$$

Do the multiplications in the fraction \frac{1\times 1}{3\times 8}.

$$\frac{1}{2}=\frac{1}{24}-2\times 0.5^{2}+c$$

Calculate 0.5 to the power of 2 and get 0.25.

$$\frac{1}{2}=\frac{1}{24}-2\times 0.25+c$$

Multiply 2 and 0.25 to get 0.5.

$$\frac{1}{2}=\frac{1}{24}-0.5+c$$

Convert decimal number 0.5 to fraction \frac{5}{10}. Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$\frac{1}{2}=\frac{1}{24}-\frac{1}{2}+c$$

Least common multiple of 24 and 2 is 24. Convert \frac{1}{24} and \frac{1}{2} to fractions with denominator 24.

$$\frac{1}{2}=\frac{1}{24}-\frac{12}{24}+c$$

Since \frac{1}{24} and \frac{12}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{2}=\frac{1-12}{24}+c$$

Subtract 12 from 1 to get -11.

$$\frac{1}{2}=-\frac{11}{24}+c$$

Swap sides so that all variable terms are on the left hand side.

$$-\frac{11}{24}+c=\frac{1}{2}$$

Add \frac{11}{24} to both sides.

$$c=\frac{1}{2}+\frac{11}{24}$$

Least common multiple of 2 and 24 is 24. Convert \frac{1}{2} and \frac{11}{24} to fractions with denominator 24.

$$c=\frac{12}{24}+\frac{11}{24}$$

Since \frac{12}{24} and \frac{11}{24} have the same denominator, add them by adding their numerators.

$$c=\frac{12+11}{24}$$

Add 12 and 11 to get 23.

$$c=\frac{23}{24}$$