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\frac{1}{2}+\frac{\left(1\times 3+1\right)\times 5}{3}
Divide \frac{1\times 3+1}{3} by \frac{1}{5} by multiplying \frac{1\times 3+1}{3} by the reciprocal of \frac{1}{5}.
\frac{1}{2}+\frac{\left(3+1\right)\times 5}{3}
Multiply 1 and 3 to get 3.
\frac{1}{2}+\frac{4\times 5}{3}
Add 3 and 1 to get 4.
\frac{1}{2}+\frac{20}{3}
Multiply 4 and 5 to get 20.
\frac{3}{6}+\frac{40}{6}
Least common multiple of 2 and 3 is 6. Convert \frac{1}{2} and \frac{20}{3} to fractions with denominator 6.
\frac{3+40}{6}
Since \frac{3}{6} and \frac{40}{6} have the same denominator, add them by adding their numerators.
\frac{43}{6}
Add 3 and 40 to get 43.