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factor(\frac{\sqrt{3}}{2\left(\sqrt{3}\right)^{2}}-\sqrt{x^{2}-4})
Rationalize the denominator of \frac{1}{2\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
factor(\frac{\sqrt{3}}{2\times 3}-\sqrt{x^{2}-4})
The square of \sqrt{3} is 3.
factor(\frac{\sqrt{3}}{6}-\sqrt{x^{2}-4})
Multiply 2 and 3 to get 6.
\frac{\sqrt{3}-6\sqrt{x^{2}-4}}{6}
Factor out \frac{1}{6}.