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\frac{\sqrt{3}}{2\left(\sqrt{3}\right)^{2}}-\frac{1}{6}
Rationalize the denominator of \frac{1}{2\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{\sqrt{3}}{2\times 3}-\frac{1}{6}
The square of \sqrt{3} is 3.
\frac{\sqrt{3}}{6}-\frac{1}{6}
Multiply 2 and 3 to get 6.
\frac{\sqrt{3}-1}{6}
Since \frac{\sqrt{3}}{6} and \frac{1}{6} have the same denominator, subtract them by subtracting their numerators.