Solve 1/2sqrt{frac{1{4}}}-1/(frac{1{4})^2}+C=-15/4

$$\frac { 1 } { 2 \sqrt { \frac { 1 } { 4 } } } - \frac { 1 } { ( \frac { 1 } { 4 } ) ^ { 2 } } + C = - \frac { 15 } { 4 }$$

Solve for C

$$C = \frac{45}{4} = 11\frac{1}{4} = 11.25$$

Steps for Solving Linear Equation

Rewrite the square root of the division \frac{1}{4} as the division of square roots \frac{\sqrt{1}}{\sqrt{4}}. Take the square root of both numerator and denominator.

$$\frac{1}{2\times \frac{1}{2}}-\frac{1}{\left(\frac{1}{4}\right)^{2}}+C=-\frac{15}{4}$$

Cancel out 2 and 2.

$$\frac{1}{1}-\frac{1}{\left(\frac{1}{4}\right)^{2}}+C=-\frac{15}{4}$$

Anything divided by one gives itself.

$$1-\frac{1}{\left(\frac{1}{4}\right)^{2}}+C=-\frac{15}{4}$$

Calculate \frac{1}{4} to the power of 2 and get \frac{1}{16}.

$$1-\frac{1}{\frac{1}{16}}+C=-\frac{15}{4}$$

Divide 1 by \frac{1}{16} by multiplying 1 by the reciprocal of \frac{1}{16}.

$$1-1\times 16+C=-\frac{15}{4}$$

Multiply 1 and 16 to get 16.

$$1-16+C=-\frac{15}{4}$$

Subtract 16 from 1 to get -15.

$$-15+C=-\frac{15}{4}$$

Add 15 to both sides.

$$C=-\frac{15}{4}+15$$

Convert 15 to fraction \frac{60}{4}.

$$C=-\frac{15}{4}+\frac{60}{4}$$

Since -\frac{15}{4} and \frac{60}{4} have the same denominator, add them by adding their numerators.

$$C=\frac{-15+60}{4}$$

Add -15 and 60 to get 45.

$$C=\frac{45}{4}$$