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\frac{1}{18}-\frac{i\sqrt{3}}{6\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{i}{6\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{1}{18}-\frac{i\sqrt{3}}{6\times 3}
The square of \sqrt{3} is 3.
\frac{1}{18}-\frac{i\sqrt{3}}{18}
Multiply 6 and 3 to get 18.
\frac{1}{18}-\frac{1}{18}i\sqrt{3}
Divide i\sqrt{3} by 18 to get \frac{1}{18}i\sqrt{3}.