Solve 1/16div3/4+3/6*4/25

$$\frac { 1 } { 16 } \div \frac { 3 } { 4 } + \frac { 3 } { 6 } \times \frac { 4 } { 25 }$$

Evaluate

$$\frac{49}{300}\approx 0.163333333$$

Solution Steps

Divide \frac{1}{16} by \frac{3}{4} by multiplying \frac{1}{16} by the reciprocal of \frac{3}{4}.

$$\frac{1}{16}\times \frac{4}{3}+\frac{3}{6}\times \frac{4}{25}$$

Multiply \frac{1}{16} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 4}{16\times 3}+\frac{3}{6}\times \frac{4}{25}$$

Do the multiplications in the fraction \frac{1\times 4}{16\times 3}.

$$\frac{4}{48}+\frac{3}{6}\times \frac{4}{25}$$

Reduce the fraction \frac{4}{48} to lowest terms by extracting and canceling out 4.

$$\frac{1}{12}+\frac{3}{6}\times \frac{4}{25}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{1}{12}+\frac{1}{2}\times \frac{4}{25}$$

Multiply \frac{1}{2} times \frac{4}{25} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1}{12}+\frac{1\times 4}{2\times 25}$$

Do the multiplications in the fraction \frac{1\times 4}{2\times 25}.

$$\frac{1}{12}+\frac{4}{50}$$

Reduce the fraction \frac{4}{50} to lowest terms by extracting and canceling out 2.

$$\frac{1}{12}+\frac{2}{25}$$

Least common multiple of 12 and 25 is 300. Convert \frac{1}{12} and \frac{2}{25} to fractions with denominator 300.

$$\frac{25}{300}+\frac{24}{300}$$

Since \frac{25}{300} and \frac{24}{300} have the same denominator, add them by adding their numerators.

$$\frac{25+24}{300}$$

Add 25 and 24 to get 49.

$$\frac{49}{300}$$

Factor

$$\frac{7 ^ {2}}{2 ^ {2} \cdot 3 \cdot 5 ^ {2}} = 0.16333333333333333$$