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\frac{1}{120}x-\frac{2}{24}-\frac{2}{6}-1-2
Divide 2 by 2 to get 1.
\frac{1}{120}x-\frac{1}{12}-\frac{2}{6}-1-2
Reduce the fraction \frac{2}{24} to lowest terms by extracting and canceling out 2.
\frac{1}{120}x-\frac{1}{12}-\frac{1}{3}-1-2
Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.
\frac{1}{120}x-\frac{1}{12}-\frac{4}{12}-1-2
Least common multiple of 12 and 3 is 12. Convert -\frac{1}{12} and \frac{1}{3} to fractions with denominator 12.
\frac{1}{120}x+\frac{-1-4}{12}-1-2
Since -\frac{1}{12} and \frac{4}{12} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{120}x-\frac{5}{12}-1-2
Subtract 4 from -1 to get -5.
\frac{1}{120}x-\frac{5}{12}-\frac{12}{12}-2
Convert 1 to fraction \frac{12}{12}.
\frac{1}{120}x+\frac{-5-12}{12}-2
Since -\frac{5}{12} and \frac{12}{12} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{120}x-\frac{17}{12}-2
Subtract 12 from -5 to get -17.
\frac{1}{120}x-\frac{17}{12}-\frac{24}{12}
Convert 2 to fraction \frac{24}{12}.
\frac{1}{120}x+\frac{-17-24}{12}
Since -\frac{17}{12} and \frac{24}{12} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{120}x-\frac{41}{12}
Subtract 24 from -17 to get -41.
\frac{x-410}{120}
Factor out \frac{1}{120}.
x-410
Consider x-10-40-120-240. Multiply and combine like terms.
\frac{x-410}{120}
Rewrite the complete factored expression.