Solve 1/12-1/10+1/4-1/3+1=

$$\frac { 1 } { 12 } - \frac { 1 } { 10 } + \frac { 1 } { 4 } - \frac { 1 } { 3 } + 1 =$$

Evaluate

$$\frac{9}{10}=0.9$$

Solution Steps

Least common multiple of 12 and 10 is 60. Convert \frac{1}{12} and \frac{1}{10} to fractions with denominator 60.

$$\frac{5}{60}-\frac{6}{60}+\frac{1}{4}-\frac{1}{3}+1$$

Since \frac{5}{60} and \frac{6}{60} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-6}{60}+\frac{1}{4}-\frac{1}{3}+1$$

Subtract 6 from 5 to get -1.

$$-\frac{1}{60}+\frac{1}{4}-\frac{1}{3}+1$$

Least common multiple of 60 and 4 is 60. Convert -\frac{1}{60} and \frac{1}{4} to fractions with denominator 60.

$$-\frac{1}{60}+\frac{15}{60}-\frac{1}{3}+1$$

Since -\frac{1}{60} and \frac{15}{60} have the same denominator, add them by adding their numerators.

$$\frac{-1+15}{60}-\frac{1}{3}+1$$

Add -1 and 15 to get 14.

$$\frac{14}{60}-\frac{1}{3}+1$$

Reduce the fraction \frac{14}{60} to lowest terms by extracting and canceling out 2.

$$\frac{7}{30}-\frac{1}{3}+1$$

Least common multiple of 30 and 3 is 30. Convert \frac{7}{30} and \frac{1}{3} to fractions with denominator 30.

$$\frac{7}{30}-\frac{10}{30}+1$$

Since \frac{7}{30} and \frac{10}{30} have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-10}{30}+1$$

Subtract 10 from 7 to get -3.

$$\frac{-3}{30}+1$$

Reduce the fraction \frac{-3}{30} to lowest terms by extracting and canceling out 3.

$$-\frac{1}{10}+1$$

Convert 1 to fraction \frac{10}{10}.

$$-\frac{1}{10}+\frac{10}{10}$$

Since -\frac{1}{10} and \frac{10}{10} have the same denominator, add them by adding their numerators.

$$\frac{-1+10}{10}$$

Add -1 and 10 to get 9.

$$\frac{9}{10}$$

Factor

$$\frac{3 ^ {2}}{2 \cdot 5} = 0.9$$