Solve for a
a=\frac{7}{8}=0.875
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Linear Equation
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\frac { 1 } { 10 } ( a + 1 ) = \frac { 1 } { 6 } ( 2 - a )
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\frac{1}{10}a+\frac{1}{10}=\frac{1}{6}\left(2-a\right)
Use the distributive property to multiply \frac{1}{10} by a+1.
\frac{1}{10}a+\frac{1}{10}=\frac{1}{6}\times 2+\frac{1}{6}\left(-1\right)a
Use the distributive property to multiply \frac{1}{6} by 2-a.
\frac{1}{10}a+\frac{1}{10}=\frac{2}{6}+\frac{1}{6}\left(-1\right)a
Multiply \frac{1}{6} and 2 to get \frac{2}{6}.
\frac{1}{10}a+\frac{1}{10}=\frac{1}{3}+\frac{1}{6}\left(-1\right)a
Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.
\frac{1}{10}a+\frac{1}{10}=\frac{1}{3}-\frac{1}{6}a
Multiply \frac{1}{6} and -1 to get -\frac{1}{6}.
\frac{1}{10}a+\frac{1}{10}+\frac{1}{6}a=\frac{1}{3}
Add \frac{1}{6}a to both sides.
\frac{4}{15}a+\frac{1}{10}=\frac{1}{3}
Combine \frac{1}{10}a and \frac{1}{6}a to get \frac{4}{15}a.
\frac{4}{15}a=\frac{1}{3}-\frac{1}{10}
Subtract \frac{1}{10} from both sides.
\frac{4}{15}a=\frac{10}{30}-\frac{3}{30}
Least common multiple of 3 and 10 is 30. Convert \frac{1}{3} and \frac{1}{10} to fractions with denominator 30.
\frac{4}{15}a=\frac{10-3}{30}
Since \frac{10}{30} and \frac{3}{30} have the same denominator, subtract them by subtracting their numerators.
\frac{4}{15}a=\frac{7}{30}
Subtract 3 from 10 to get 7.
a=\frac{7}{30}\times \frac{15}{4}
Multiply both sides by \frac{15}{4}, the reciprocal of \frac{4}{15}.
a=\frac{7\times 15}{30\times 4}
Multiply \frac{7}{30} times \frac{15}{4} by multiplying numerator times numerator and denominator times denominator.
a=\frac{105}{120}
Do the multiplications in the fraction \frac{7\times 15}{30\times 4}.
a=\frac{7}{8}
Reduce the fraction \frac{105}{120} to lowest terms by extracting and canceling out 15.
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