Solve 1/10+6/10*3/1=

$$\frac { 1 } { 10 } + \frac { 6 } { 10 } \times \frac { 3 } { 1 } =$$

Evaluate

$$\frac{19}{10}=1.9$$

Solution Steps

Reduce the fraction \frac{6}{10} to lowest terms by extracting and canceling out 2.

$$\frac{1}{10}+\frac{3}{5}\times \frac{3}{1}$$

Anything divided by one gives itself.

$$\frac{1}{10}+\frac{3}{5}\times 3$$

Express \frac{3}{5}\times 3 as a single fraction.

$$\frac{1}{10}+\frac{3\times 3}{5}$$

Multiply 3 and 3 to get 9.

$$\frac{1}{10}+\frac{9}{5}$$

Least common multiple of 10 and 5 is 10. Convert \frac{1}{10} and \frac{9}{5} to fractions with denominator 10.

$$\frac{1}{10}+\frac{18}{10}$$

Since \frac{1}{10} and \frac{18}{10} have the same denominator, add them by adding their numerators.

$$\frac{1+18}{10}$$

Add 1 and 18 to get 19.

$$\frac{19}{10}$$

Factor

$$\frac{19}{2 \cdot 5} = 1\frac{9}{10} = 1.9$$