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\frac{1}{1-\frac{1}{1+\frac{1}{3-\frac{1}{\frac{1}{6}+\frac{2}{6}}}}}
Least common multiple of 6 and 3 is 6. Convert \frac{1}{6} and \frac{1}{3} to fractions with denominator 6.
\frac{1}{1-\frac{1}{1+\frac{1}{3-\frac{1}{\frac{1+2}{6}}}}}
Since \frac{1}{6} and \frac{2}{6} have the same denominator, add them by adding their numerators.
\frac{1}{1-\frac{1}{1+\frac{1}{3-\frac{1}{\frac{3}{6}}}}}
Add 1 and 2 to get 3.
\frac{1}{1-\frac{1}{1+\frac{1}{3-\frac{1}{\frac{1}{2}}}}}
Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.
\frac{1}{1-\frac{1}{1+\frac{1}{3-1\times 2}}}
Divide 1 by \frac{1}{2} by multiplying 1 by the reciprocal of \frac{1}{2}.
\frac{1}{1-\frac{1}{1+\frac{1}{3-2}}}
Multiply 1 and 2 to get 2.
\frac{1}{1-\frac{1}{1+\frac{1}{1}}}
Subtract 2 from 3 to get 1.
\frac{1}{1-\frac{1}{1+1}}
Anything divided by one gives itself.
\frac{1}{1-\frac{1}{2}}
Add 1 and 1 to get 2.
\frac{1}{\frac{2}{2}-\frac{1}{2}}
Convert 1 to fraction \frac{2}{2}.
\frac{1}{\frac{2-1}{2}}
Since \frac{2}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{1}{\frac{1}{2}}
Subtract 1 from 2 to get 1.
1\times 2
Divide 1 by \frac{1}{2} by multiplying 1 by the reciprocal of \frac{1}{2}.
2
Multiply 1 and 2 to get 2.