Solve 1/1*1/2+1/6+1/8

$$\frac { 1 } { 1 } \cdot \frac { 1 } { 2 } + \frac { 1 } { 6 } + \frac { 1 } { 8 }$$

Evaluate

$$\frac{19}{24}\approx 0.791666667$$

Solution Steps

Divide 1 by 1 to get 1.

$$1\times \frac{1}{2}+\frac{1}{6}+\frac{1}{8}$$

Multiply 1 and \frac{1}{2} to get \frac{1}{2}.

$$\frac{1}{2}+\frac{1}{6}+\frac{1}{8}$$

Least common multiple of 2 and 6 is 6. Convert \frac{1}{2} and \frac{1}{6} to fractions with denominator 6.

$$\frac{3}{6}+\frac{1}{6}+\frac{1}{8}$$

Since \frac{3}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$\frac{3+1}{6}+\frac{1}{8}$$

Add 3 and 1 to get 4.

$$\frac{4}{6}+\frac{1}{8}$$

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$\frac{2}{3}+\frac{1}{8}$$

Least common multiple of 3 and 8 is 24. Convert \frac{2}{3} and \frac{1}{8} to fractions with denominator 24.

$$\frac{16}{24}+\frac{3}{24}$$

Since \frac{16}{24} and \frac{3}{24} have the same denominator, add them by adding their numerators.

$$\frac{16+3}{24}$$

Add 16 and 3 to get 19.

$$\frac{19}{24}$$

Factor

$$\frac{19}{2 ^ {3} \cdot 3} = 0.7916666666666666$$