Solve 1/1+3/5+(-1/2)^3=

$$\frac { 1 } { 1 } + \frac { 3 } { 5 } + ( - \frac { 1 } { 2 } ) ^ { 3 } =$$

Evaluate

$$\frac{59}{40}=1.475$$

Solution Steps

Divide 1 by 1 to get 1.

$$1+\frac{3}{5}+\left(-\frac{1}{2}\right)^{3}$$

Convert 1 to fraction \frac{5}{5}.

$$\frac{5}{5}+\frac{3}{5}+\left(-\frac{1}{2}\right)^{3}$$

Since \frac{5}{5} and \frac{3}{5} have the same denominator, add them by adding their numerators.

$$\frac{5+3}{5}+\left(-\frac{1}{2}\right)^{3}$$

Add 5 and 3 to get 8.

$$\frac{8}{5}+\left(-\frac{1}{2}\right)^{3}$$

Calculate -\frac{1}{2} to the power of 3 and get -\frac{1}{8}.

$$\frac{8}{5}-\frac{1}{8}$$

Least common multiple of 5 and 8 is 40. Convert \frac{8}{5} and \frac{1}{8} to fractions with denominator 40.

$$\frac{64}{40}-\frac{5}{40}$$

Since \frac{64}{40} and \frac{5}{40} have the same denominator, subtract them by subtracting their numerators.

$$\frac{64-5}{40}$$

Subtract 5 from 64 to get 59.

$$\frac{59}{40}$$

Factor

$$\frac{59}{2 ^ {3} \cdot 5} = 1\frac{19}{40} = 1.475$$