Solve 1/1+(frac{30,5{26,55})^2}=

$$\frac { 1 } { 1 + ( \frac { 30,5 } { 26,55 } ) ^ { 2 } } =$$

Evaluate

$$\frac{281961}{654061}\approx 0,431092819$$

Solution Steps

Expand \frac{30,5}{26,55} by multiplying both numerator and the denominator by 100.

$$\frac{1}{1+\left(\frac{3050}{2655}\right)^{2}}$$

Reduce the fraction \frac{3050}{2655} to lowest terms by extracting and canceling out 5.

$$\frac{1}{1+\left(\frac{610}{531}\right)^{2}}$$

Calculate \frac{610}{531} to the power of 2 and get \frac{372100}{281961}.

$$\frac{1}{1+\frac{372100}{281961}}$$

Add 1 and \frac{372100}{281961} to get \frac{654061}{281961}.

$$\frac{1}{\frac{654061}{281961}}$$

Divide 1 by \frac{654061}{281961} by multiplying 1 by the reciprocal of \frac{654061}{281961}.

$$1\times \frac{281961}{654061}$$

Multiply 1 and \frac{281961}{654061} to get \frac{281961}{654061}.

$$\frac{281961}{654061}$$

Factor

$$\frac{3 ^ {4} \cdot 59 ^ {2}}{89 \cdot 7349} = 0.4310928185597368$$