Solve 1/1+1{frac{7/2-3}}

$$\frac { 1 } { 1 + \frac { 1 } { \frac { 7 } { 2 } - 3 } }$$

Evaluate

$$\frac{1}{3}\approx 0.333333333$$

Solution Steps

Convert 3 to fraction \frac{6}{2}.

$$\frac{1}{1+\frac{1}{\frac{7}{2}-\frac{6}{2}}}$$

Since \frac{7}{2} and \frac{6}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{1+\frac{1}{\frac{7-6}{2}}}$$

Subtract 6 from 7 to get 1.

$$\frac{1}{1+\frac{1}{\frac{1}{2}}}$$

Divide 1 by \frac{1}{2} by multiplying 1 by the reciprocal of \frac{1}{2}.

$$\frac{1}{1+1\times 2}$$

Multiply 1 and 2 to get 2.

$$\frac{1}{1+2}$$

Add 1 and 2 to get 3.

$$\frac{1}{3}$$

Factor

$$\frac{1}{3} = 0.3333333333333333$$