Solve 1/(-2+alpha)(-4+alpha)=

$$\frac { 1 } { ( - 2 + \alpha ) ( - 4 + \alpha ) } =$$

Evaluate

$$\frac{1}{\left(\alpha -4\right)\left(\alpha -2\right)}$$

Solution Steps

Apply the distributive property by multiplying each term of -2+\alpha by each term of -4+\alpha .

$$\frac{1}{8-2\alpha -4\alpha +\alpha ^{2}}$$

Combine -2\alpha and -4\alpha to get -6\alpha .

$$\frac{1}{8-6\alpha +\alpha ^{2}}$$

Expand

$$\frac{1}{\left(\alpha -4\right)\left(\alpha -2\right)}$$

Solution Steps

Apply the distributive property by multiplying each term of -2+\alpha by each term of -4+\alpha .

$$\frac{1}{8-2\alpha -4\alpha +\alpha ^{2}}$$

Combine -2\alpha and -4\alpha to get -6\alpha .

$$\frac{1}{8-6\alpha +\alpha ^{2}}$$